2023年广西名校高考冲刺模拟数学试题含解析

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2023
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⚪Ḅᐵ᫏⚪7.Aூ᪆௃ᐜᑭᵨᦪᦪḄᑣᑣz,ᓽ᪷"ᦪḄ#$%Iz|.ூ&௃VZ=-^+(1+Z)2=1-Z+2Z=1+Z,.•.|Z|=JF+I2=0.ᦑ⌱)A.ூ*+௃,⚪-⌕ὃ0ᦪᦪḄᑣᑣḄ1ᵨ23ᦪḄ#$%Ḅ1ᵨ4᧕⚪.8.Bூ᪆௃ᵫ⚪89:(-£)+/=CD31+9=஻F+1ᦑᨵ0=2H-Q+1জJ᪷":L912ঝ,4422G34ᵫজঝ9஺ḄᨬᜧQRSজḄTUQVWᩩY.ூ&௃)Zᦪf(x)=sin(0x+9)(ty>O,\(p\„y),x=—\]/(x)Ḅ^*X=_]y=/(x)`aḄbcd44JTJTTT.,ᑗ•(hh)+᜛=᝕kD+0=/4+—,kஹk!GZ,...l=2(஻-2)+1,ᓽᑓ]᜻ᦪজ.442oᓫq.LL.q-3,.”,12ঝ.4326934ᵫজ©9⁐ḄᨬᜧQ]1.

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11h)±஺஺|Ì஺2Ḅ᜜³ᙊµ¶OM=2,R=S=284L)OO]=BR=BS=28R½)¾ACBOḄ᜜³ᙊµ¶CE,ᑣA"=CW=3,CE=4,ME=1,AEWAC=3C/cos/AEC=-^^=,362R=———=^^=2ÑrsinZA£C=),sinZA£C373R=Ñ,S=28F.2Öᦑ⌱)Aூ*+௃×⚪ὃ0½Ø┵Ḅ᜜³ᳫ⊤☢¼ᐵ*ÚÛ©ªᐵÜ9ᳫÝÞÁᳫ¸¶ßàáà᧕⚪â.11.Dூ᪆௃ᑭᵨᦪᦪḄã◀ᓄ¨Jᵫᦪ#Ḅ$%.ூ&௃)•.ফ(l+i)=-2+2i,•••ᦪ2/(1+0Ḅ#]7(-2)2+22=2ç.ᦑ⌱)D.ூ*+௃,⚪-⌕ὃ0ᦪᦪḄã◀ὃ0ᦪ#Ḅ¬Ạ⚪.12.Cூ᪆௃ᵫ¬,èḄéêḄëì9/=*(஻eN*),ᑭᵨ/=_=*9ï=ncoAneN*),ᓽᑨñ⌱⚗.T2ᐔூ&௃

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15=2\/2sin(2a+?)+2,•.a=((ᕜ=2"+2.ூ௃⚪ὃᦪஹ᩽ᙶ᪗Ḅᓄ"⚪᩽#Ḅ$%&'()*ᦪḄឤ,-ᣚ/01᫏⚪.18.(1)—(2)3+3733ூ
᪆௃(1)ᑭᵨ56Ḅ7)89:)()*ᦪᐵ<9ᓄ=᦮ᳮ@AᔠDOVAVTT,EFAḄG.(2)ᵫI6$ᳮEFa,ᑭᵨ56$ᳮEJcGᓽEFᕜL.ூ
௃1-AL(1),/2^sin2M+sinA—V3=02...2[3xi~COsA+sinA-y/3=0yf2ᓽsinA-V3cosA=0/.tanA=G:OOVA/3sin—=3,sinA3VAC=6=6ᵫ56$ᳮJa2=b2+c2-2bccosA,--6=0Vc>0,ᡠ&Jc=2RᕜLa+b+c=3+36.ூ௃⚪ὃ()*ᦪឤ,-ᣚḄSᵨI6$ᳮ56$ᳮᙠU()V1ḄSᵨὃWᓄXY/01᫏⚪.19.(1)040,/(x)ᙠ(0,+࠷)[ᓫ]⌴_aு0Ax)ᙠ(0,஺)[⌴cᙠ3m)[⌴_.(2)(-oo,-U.ூ
᪆௃(1)Fde*ᦪ/’(h)ᑖjklᵫ/'(x)>0m$_noᵫ/'(x)<0m$cnop(2)ᵫ/প=0,ᑭᵨ(1)✌ᐜJᡈa=l,Fd/(x)-g(x)ḄᨬvGᓽEJAl.

16ூ6௃(1)ᦪaå(0,+8),)¦-=XXXr(x)>o,஻x)ᓫç⌴éÝ“>()P/'(x)=0#x=a,0஺f'(x)>0,f(x)⌴éìᡠíîᙠ(0,+8)ᓫç⌴é஻>0/(îᙠ(0,஺)⌴ëᙠ(a,y)⌴é.(2)᧕È/(1)=0,ᵫᦪᓫçឋðᨵñ}ò]ᑣᡈ஺=1.a-\1a40g(x)=----/(x)-g(x)=lnx+——a,XX=◤a=0/(õ)-g(x)2öឤᡂmᓽmf(x)=InxH----1,ex1Yx—1I—X11Pt(x)=/(x)—g(x)=lnx+——1ᵫ«î=————=(x-l)(—+F),È(X)ᙠ(0,1)⌴ëᙠ(1,ý)xexexe⌴é/ᯅ=«1)=-1ù4}1.ìᡠíùḄ®5°(}%-1].ூ]^௃⚪ὃᵨÿᦪẆᦪḄᓫឋὃᦪᦪឤᡂ⚪⚪ᐵᙠᓄឤᡂ⚪ᓄ!ᦪḄᨬ#.%&'()ᦪ!.20.(1)0᪆(2)0᪆ூ᪆௃(1)!)4ᑖ᪆)ᦪḄ678ᑨ:ᓫឋᓽ'.—4Inx41nx21n,ফg(x)=-------+C,g(x)ᨵGHI------+C=0Kᦪ᪷8ᣚᐗOPHIᓄb=——8!)ᑖXXtQ/ஹ21nz᪆U()=----ḄVWᦪXYᔠ!ᓽ'.

17ூwU௃.4—4,(1)fMḄ$%xy(0,+8),(z=+x=02,/'(X)>0,ᡠ&y=/(x)ᙠ(2,+8)ᓫ]⌴_ᡠ&y=f(x)Ḅcnoy(0,2),_noy(2,+8).—41nxzllnx21nl(2)g(x)=-----+bx,g(x)ᨵ,0--------+=0ᦪ᪷=t(t>0)ᑣWᓄyb=——,XXt=஻'=./=0,/=e,.\e(0,e),஻'Q)>0/€(e,+oo),/“f)<0,2I஻(max=h(e)=Mr=M,h(t)=-2e<°,r>e,஻)>0.ee᝞EজᓃW0஻ᨵMᓽg(x)ᨵMp2ঝ0<%(M஻ᨵᓽg(x)ᨵpeoঞb=—ᨵMᓽg(x)ᨵMpe2ট>M,஻hᓽg(x)h.eூ௃⚪⌕ὃᑭᵨeᦪᑖ᪆*ᦪḄᓫ]ឋḄ¢:£ὃᑭᵨeᦪᑖ᪆*ᦪḄ"⚪,/01᫏⚪.21.(1)(xT)2+y2=4,¤¥1Ḅ¤)ᙶ᪗yx-y—2=0q(2)3.ூU᪆௃(1)¦Jᑮ¨¥Ḅᑭᵨ᩽ᙶ᪗¤)ᙶ᪗Ḅᓄ89FJ¤¥Ḅ¤)ᙶ᪗p(2)ᐜJᑮ¤¥Ḅᦪ©¤¥ḄᦪªᐭᑮᙊḄJᑮᐵ0/ḄMᐗ®ᵫ᪷¯<ᦪḄᐵ<ஹᦪḄ°±²%³´FU.ூwU௃পᵫ¨¥CḄᦪ2c(ayᦪ)=0M(ayᦪ)ly=2sinaly=2sina9µ¶·J¨¥CḄy(x—l)2+y2=4
ᵫ¤¥1Ḅ᩽ᙶ᪗EJpcosOcos-j-psiwOsi/z-j-==>pcos0—psi/iO=2,

18ᓽst1Ḅsuᙶ᪗HIx-y-2=0.fx=2+^t,(2)ᵫ⚪y'zP(2,0),ᑣst1Ḅ}ᦪHI~(t}ᦪ).A,BḄ}ᦪᑖti,t2,ᑣ|PAHPB|=|hHt2l,fx=2+^t,OI(t}ᦪ)ᐭ(x—l)z+y2=4,zt?+3=0,lr=2t!|A>0,ᵫᳮ'zt/t2=-3,ᡠ|PAHPB|=|-3|=3.22.(I)0᪆(II)b>-

192ூ᪆௃(1)ᵫ⚪X>0,l+ᵫf(X)ᙠX=X1,X2(X/X2)ᜐ)ᦪzᑮ/'()=/'(%2)=஻?z11,-------F1-??/=0᳝X,111I-2----F]_"2=()ᵫᳮz‘+'=1,ᵫ£¤z+%=%%>2¥z%¦§2>4,ᵫ⚪yzX\X2f(%)+/(¨)=᳝©ª(«©)],¬=%“2>4,!|©In(᳝஽)1=Im—1,¬g(t)=t-

20t-l(t>4),,ᑭᵨ)ᦪឋ±²³´g(/)>g(4)=3—21n2.(2)ᵫ஻x)=µ+஻zz=¬/©¦ITXXᑭᵨ¸³C'³´³´h(x)<1ឤᡂ.ᵫ¹yµ(3,1),ᑘ»)=¼½ᨵzU(x)(0,+<»)¿Ḅ⌴Áᦪ./(ὡ=ÃÄÅ”“zX2?b>——lnr+1,¬Ç(x)=——lnx+l(x>0),ᵫÈ'!஻ḄÉ#Ë..ூ௃

2112----------1-1-m=0zÐX¬/'ÌÍ=/'ÌÎ2Í=Ï1τ¸----------1-1-/77=02[x211τᵫᳮz+—=1¨Ñᓽ%+%2=%஺§2>2"Ó,zX1•஽>4(xj+/(X2)=(Ô1+%2)——τ------------(InXj+Inx^)\X\X27=Õln(x%2)-l¬r=᳝>4,Ulll=z-ln/-l,¬g(r)=r-lnf-l(r>4),ᑣg'()=l;>0“>4),zg(/)>g(4)=3—21n2(IDᵫ.f(x)"+)z“x—Tx”K-X1τ,Ax------Inx-b¬஻(x)=-...............X!lx-0+,xr+oo,஻(x)->1×☢ᐜ³´஻x0),!=——=—XXXXz02w(x),=஻?(2)=-ln2mxூô௃¤⚪ὃᦪḄᓫឋ)ᦪḄõö÷ᐸᵨùèὃúûüý²Uþÿᔠ
ᵨ⚪.