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ID:13066401
大小:42.50 KB
页数:13页
时间:2018-07-20
《板式楼梯梯板厚度确定(the thickness of the plate staircase is determined)》由会员上传分享,免费在线阅读,更多相关内容在教育资源-天天文库。
1、板式楼梯梯板厚度确定(Thethicknessoftheplatestaircaseisdetermined)[collectionofdocuments]:thethicknessoftheplatestaircaseisdeterminedThethicknessoftheplatestaircaseisdeterminedTime:Theplatethicknessoftheboardis1/25~1/30l,andthenetstepoftheboardstairis4M,butmanyframestructuresarelargert
2、han4M,andhowshouldthethicknessoftheplatebedetermined?(onlysteponthesideoftheladderbeam,andontheothersideoftherestplatform)ASA:Accordingtotheactualplatespanof1/25,ifthethicknessoftheplateisgreaterthan250mm,itisindicatedthatthestructureplanischangedHHH:Itissaidthat"thenetstepo
3、ftheboardstair"ismainlyfromaneconomicpointofview,andtheactualprojectis6meterscommon.Whenthespanislarge,thethicknessoftheboardismainlycontrolledbydeflection,and1/25-1/30lisreasonableNewx:A3,600-spanstaircase,thethicknessoftheboardshouldbemadeof140,seemsalittletoothick,Thefoll
4、owingisattachedwiththeslidebookofthetable:tb-2I.basicinformation:Projectname:project1Thestairstype:platetypeA(╱)bearingcondition:elasticonbothendsThehorizontalprojectionlengthoftheladderisLo1=3600mm,whichisequaltoLo1=3600mmNetwidthofladderplateB=1200mmSlabthicknessh1=140mmHe
5、ightHv=1500mmstaircaseseriesn=10Lowersupportwidthd1=200mmuppersupportwidthd2=200mmLinearconstantloadPk=0.00kN/mUniformliveloadqk=3.00kN/mbitsofc=0.7bitsofq=0.6Thicknessofsurfacelayerc1=25mmceilingthicknessc2=20mmSurface,ceilingdensitygammac=20.00kN/mstairweightdensitygamma
6、b=25.00kN/mStrengthgradeofconcrete:C25Fc=11.94ft=1.27FTK=1.78N/mmEc=27871N/mmSteelbarintensitydesignvaluefy=210n/mmEs=210000n/mmThelongitudinalreinforcementpointstothenearedgedistanceas=25mm2.Calculationresults:1.Stairgeometryparameters:Stepheightt=Hv/n=1500/10=150.0mmS
7、tepwidthw=Lo1/(n-1)=3600/(10-1)=400.0mmBenchrampAnglealpha=ArcTan(t/w)=ArcTan(150.0/400.0)=20.6°LaddersectionofthelengthoftheinclinedplateLx=Lo1/cosinealpha=3600/Cos20.6°=3845mmLadderplatethicknesstotheverticalheightoftheh1'=h1/cosinealpha=140/Cos20.6°=150mmT=(T+2*h1')/2=(15
8、0+2*150)/2=225mmLadderplateeffectiveheight:h1o=h1-as=140-25=115mm2.Loaddesi
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