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1、专题十六 椭圆、双曲线、抛物线1.已知双曲线-=1的右焦点与抛物线y2=12x的焦点重合,则该双曲线的焦点到其渐近线的距离等于( ). A.B.4C.3D.5答案:A [易求得抛物线y2=12x的焦点为(3,0),故双曲线-=1的右焦点为(3,0),即c=3,故32=4+b2,∴b2=5,∴双曲线的渐近线方程为y=±x,∴双曲线的右焦点到其渐近线的距离为=.]2.等轴双曲线C的中心在原点,焦点在x轴上,C与抛物线y2=16x的准线交于A,B两点,
2、AB
3、=4,则C的实轴长为( ).A.B.2C.4
4、D.8答案:C [抛物线y2=16x的准线方程是x=-4,所以点A(-4,2)在等轴双曲线C;x2-y2=a2(a>0)上,将点A的坐标代入得a=2,所以C的实轴长为4.]3.已知椭圆C:+=1(a>b>0)的离心率为.双曲线x2-y2=1的渐近线与椭圆C有四个交点,以这四个交点为顶点的四边形的面积为16,则椭圆C的方程为( ).[来源:学
5、科
6、网Z
7、X
8、X
9、K]A.+=1B.+=1C.+=1D.+=1答案:D [因为椭圆的离心率为,所以e==,c2=a2,c2=a2=a2-b2,所以b2=a2,即a2=4b2.双曲线的渐近线方程为y
10、=±x,代入椭圆方程得+=1,即+==1,所以x2=b2,x=±b,y2=b2,y=±b,则在第一象限双曲线的渐近线与椭圆C的交点坐标为,所以四边形的面积为4×b×b=b2=16,所以b2=5,所以椭圆方程为+=1.]anti-Japanesepatriotism.Undertheinfluenceoftheparty,Zhu,Wang,actinginstrictdiscipline,political,militaryqualityandcombateffectivenesshasimproved.Aswellasyouthserv
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