《层次分析法案例》PPT课件

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1、层次单排序列向量归一化，再将行和归一化0.1110.1300.0770.5560.6520.6920.3330.2180.231W1=(0.318,1.9,0.782)T行和为3,行和归一化为wW=(0.106,0.633,0.261)T11/51/30.1060.32AW=5130.633=1.946AW=W31/310.2610.79=1/3(0.32/0.106+1.946/0.633+0.79/0.261)=1/3*(3.019+3.074+3.027)=3.04一致性检验n=3，RI=0.58

2、CI==(3.04-3)/(3-1)=0.02CR=CI/RI=0.02/0.58=0.034<0.10通过一致性检验列向量归一化，再将行和归一化0.51920.59600.43480.51060.38880.17310.19870.26090.25530.27780.10380.06620.08700.06380.11110.12970.09930.17390.12770.16670.07420.03980.04340.04260.0556W=(2.4494,1.1658,0.4319,0.6973,0.

3、2556)T行和为5135470.4912.5211/313250.2321.178BW=1/51/311/220.092=0.4291/41/22130.1380.6991/71/51/21/310.0460.255BW=W=1/5(2.521/0.491+1.178/0.232+0.429/0.092+0.699/0.138+0.255/0.046)=1/5*25.484=5.0968一致性检验n=5，RI=1.12CI==(5.0968-5)/(5-1)=0.0242CR=CI/RI=0.0242

4、/1.12=0.0216<0.10通过一致性检验